5 请问怎么给struct里的mapping里的struct赋值。
如截图所示，我的struct City里有个goods mapping，而这个mapping的value值又是一个struct。我尝试用如图所示的方法给这个struct赋值，但是报错，我猜应该是因为这个goods是在City里的，不能为外部所用。所以我想请问下，这种情况下怎么给这个goods赋值呢？
我的代码如下：
// SPDX-License-Identifier: GPL-3.0
pragma solidity >=0.8.0 <0.9.0;
contract Market {
struct City {
uint256 cityID;
string cityName;
mapping(uint256 => SingleGoods) goods;
}
mapping(uint256 => City) citys;
struct SingleGoods {
string name;
uint256 price;
uint256 qua;
}
function init(
uint256 _cityID,
string memory _cityName,
uint256 _goodsID,
string memory _goodsName,
uint256 _goodsPrice,
uint256 _goodsQua
) public {
City storage city1 = citys[_cityID];
city1.cityID = _cityID;
city1.cityName = _cityName;
SingleGoods storage singleGoods1 = goods[_goodsID];
singleGoods1.name = _goodsName;
singleGoods1.price = _goodsPrice;
singleGoods1.qua = _goodsQua;
city1.goods = singleGoods1;
}
}
最佳答案 2022-03-13 16:54
city1.goods[_goodsID]这么用
contract Market {
struct City {
uint256 cityID;
string cityName;
mapping(uint256 => SingleGoods) goods;
}
mapping(uint256 => City) citys;
struct SingleGoods {
string name;
uint256 price;
uint256 qua;
}
function init(
uint256 _cityID,
string memory _cityName,
uint256 _goodsID,
string memory _goodsName,
uint256 _goodsPrice,
uint256 _goodsQua
) public {
City storage city1 = citys[_cityID];
city1.cityID = _cityID;
city1.cityName = _cityName;
SingleGoods storage singleGoods1 = city1.goods[_goodsID];
singleGoods1.name = _goodsName;
singleGoods1.price = _goodsPrice;
singleGoods1.qua = _goodsQua;
//city1.goods = singleGoods1;
/* City storage city1 = citys[_cityID];
city1.cityID = _cityID;
city1.cityName = _cityName;
SingleGoods memory singleGoods1 = city1.goods[_goodsID];
singleGoods1.name = _goodsName;
singleGoods1.price = _goodsPrice;*/
//citys[_cityID] = city1;
//singleGoods1.qua = _goodsQua;
//city1.goods = singleGoods1;
}
}
